Question

3/4(7x-1)-(2x-(1-x)/2)=x+3/2

Answer 1

3/4(7x - 1) - [2x - (1 - x)/2] = (x + 4)/2

(21x - 3)/4 - [4x/2 - (1 - x)/2] = (x + 4)/2

(21x - 3)/4 - (5x - 1)/2 = (x + 4)/2

(21x - 3)/4 - (10x - 2)/4 = (2x + 8)/4

21x - 3 - 10x + 2 = 2x + 8

11x - 1 = 2x + 8

9x = 9

x = 1

hope it's help u

Answer 2

Step-by-step explanation:

Given: $\frac{3}{4} x (7x-1) - \frac{(2x-(1-x)}{2} = \frac{x+3}{2}$

To find: The value of $x$

For calculation of the equation,

We need to solve and open the brackets,

⇒ $\frac{3}{4} x (7x-1) - \frac{(2x-(1-x)}{2} = \frac{x+3}{2}$

⇒ $\frac{21x - 3}{4} - 2x - \frac{(-1+x)}{2} = \frac{x+3}{2}$

⇒ $\frac{21x-3}{4} - \frac{4x}{2} - \frac{-x-1}{2} = \frac{x+3}{2}$

⇒ $\frac{21x-3}{4} - \frac{5x-1}{2} = \frac{x+3}{2}$

Now, we need to find LCM,

The LCM is 4.

⇒ $\frac{21x-3}{4} - \frac{2/(5x-1)}{2x2} = \frac{2(x+3)}{2x2}$

⇒ $\frac{21x-3}{4} - \frac{10x-2}{4} = \frac{2x+6}{4}$

⇒ $21x - 3 - 10x + 2 = 2x + 6$

⇒ $11x - 1 = 2x + 6$

⇒ $9x = 6 + 1$

⇒ $9x=7$

⇒ $x = \frac{7}{9}$ or $0.7.$

The answer is $x= \frac{7}{9}$ or $0.7.$