Question

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A boy spends of his pocket money and then of the remainder is given to his sister. If he has 40
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left, what did he have at first?
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Answer 1

Answer: ₹800

Let ₹x be the pocket money

Spends 3/4 of his pocket money =3/4*x= 3x/4

Remaining is= 1/4*x= x/4

Then gives 4/5 of the remaining to his sister,

= 4/5* x/4= x/5

Finally, 40 rupees left, how much did he have at first?

x/4-x/5=40/1

LCM= 20

5x/20-4x/20= 800/20

x/20=800/20

x= $\frac{800}{20}*20$

x= ₹800

Verification:

The 3/4 amount he spent of his pocket money:

$800*\frac{3}{4}= 200*3= 600$

₹600 was spent.

Remaining ₹200

The 4/5 of remaining amount he gave to his sister:

200*5/4= $200*\frac{4}{5}= 40*4= 160$

₹ 160 was given.

Remaining ₹40.

Since, our answer has satisfied all the conditions of the question, our answer is verified, hence showing that the answer found is the correct answer for this question...