Question

3 4. Calculate percentage error in kinetic energy of a body of mass 23 +0.1 gn and moving with velocity of 46 +0.2 cm/s​

Answer 1

Answer:

percentage error in kinetic energy of a body of mass 23 +0.1 gn and moving with velocity of 46 +0.2 cm/s is 1.3 %

Explanation:

Kinetic Energy =$\frac{1}{2}$M$V^{2}$

ΔK.E/K.E=(ΔM/M) + 2 (ΔV/V)

                =(0.1/23) + 2( 0.2/46)

                 =0.00434 + 2(0.00434)

                 =0.013

Percentage error in kinetic energy is (ΔK.E/K.E)×100

                               =0.013×100=1.3 %