Math, asked by poojithakummari2001, 10 months ago

3.4 Draw a 120 mm long line AB inclined at 60° to the
horizontal. Erect a perpendicular to AB from point
P, lying at a distance 30 mm from end A.​

Answers

Answered by sonalibasu77
0

1.First draw line AB with length of 120mm

2.Then, take a point P away from end A with a distance of 30mm.

3.With any radius, draw a 180° arc.

4.Mark the two points where the arc's ends intersect on line AB with any letter.(In this case I mark the point C&D)

5.On the point D with same radius draw a arc intersecting the 180° arc.(This is 60°)

6.Mark the arc with any letter.(In this case I mark it E)

7.Draw a line from point P the arc E. Mark the end of the line with any letter.(In this case I mark it F)

8.With same radius, draw a 180° arc.Mark the two ends of the arc with any letter.(In this case I mark it H&J)

9.With same radius draw a arc from arc H to intersect line segment PF at I(in this case I mark the intersecting point as I,we can give any letter to name the point)

10.With same radius, draw an arc on GI chord. Name the arc with any letter.

11.Draw a line through the arc. Name the line with any two letters.(In this case I mark it line JK)

This is your perpendicular line ready.

Please mark me as brainliest

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