Question

3, 4 +P and 7p
are in AP. And the value of
P​

Answer 1

Answer:

AP → 3, 4+p, 7p

$\implies \: \frac{(3 + 7p)}{2 } = 4 + p \\ \\ \implies \: 3 + 7p = 8 + 2p \\ \\ \implies7p - 2p = 8 - 3 \\ \\ \implies \: 5p = 5 \\ \\ \therefore \: p = 1$