Question

3-4 sin^2theta/cos^2theta = 3- tan^2theta​

Answer 1

Answer:

Step-by-step explanation:

3-4sin^2theta/cos^2theta

=3/cos^2theta-4sin^2theta/cos^2theta    

=3sec^2theta-4tan^2theta                        (1/cos^2theta=sec^2)

=3(1+tan^2theta)-4tan^2theta                  (sin^2theta/cos^theta=tan^2theta)

=3+3tan^2theta-4tan^2theta

=3-tan^2theta

hence lhs=rhs                                                                  

hence proved