Question

3/4 (x - 3) - (2x - 1/4x) = x + 3/5​

Answer 1

Answer:

Reffer above the attachment

Answer 2

★ Solution :-

As we are given with the variable on both LHS and RHS, it's mandatory to use the transposition method.

$\sf \leadsto \dfrac{3}{4} (x - 3) - \bigg( 2x - \dfrac{1}{4}x \bigg) = x + \dfrac{3}{5}$

$\sf \leadsto \dfrac{3x}{4} - \dfrac{9}{4} - \bigg( 2x - \dfrac{1x}{4} \bigg) = x + \dfrac{3}{5}$

$\sf \leadsto \dfrac{3x - 9}{4} - \bigg( \dfrac{8x - 1x}{4} \bigg) = \dfrac{5x + 3}{5}$

$\sf \leadsto \dfrac{3x - 9}{4} - \dfrac{7x}{4} = \dfrac{5x + 3}{5}$

$\sf \leadsto \dfrac{3x - 9 - 7x}{4} = \dfrac{5x + 3}{5}$

$\sf \leadsto \dfrac{-4x - 9}{4} = \dfrac{5x + 3}{5}$

$\sf \leadsto 5(-4x - 9) = 4(5x + 3)$

$\sf \leadsto -20x - 45 = 20x + 12$

$\sf \leadsto -20x - 20x = 12 + 45$

$\sf \leadsto -40x = 57$

$\sf \leadsto x = \dfrac{57}{-40}$

$\sf \leadsto x = \dfrac{-57}{40}$

Therefore, the value of x is $\sf \dfrac{-57}{40}$.