Question

(3^41) + (3^42) + (3^43) + (3^44) + (3^45) can be fully devicible with?
a) 4
b)5
c)11
d)17​

Answer 1

Answer:

AnSwEr{a}^{2} - 2ab + {b}^{2} - {c}^{2}a

2−2ab+b 2−c 2{(a - b)}^{2} - {(c)}^{2}(a−b)2 −(c) 2(a - b - c)(a - b + c)(a−b−c)(a−b+c)HEARTLESS BoY♡HEARTLESSBoY♡