Question

3.42 g of sucrose are dissolved in 18 g of water in a beaker. The number of oxygen atoms in the solution are

Answer 1

Answer:Sucrose is C12H22O11.

Molar mass of sucrose = 12×12 + 1×22 + 16×11 = 342 g

342 g of sucrose = 1 mol of sucrose

So, 3.42 g of sucrose = 0.01 mol

Oxygen atoms in 1 mol of sucrose = 11 × 6.022 × 1023

So, oxygen atoms in 0.01 mol of sucrose = 0.01 × 11 × 6.022 × 1023 = 6.6242 × 1022

18 g of water (H2O) = 1 mol of water

Oxygen atoms in 1 mol of water = 6.022 × 1023

Total oxygen atoms = 6.6242 × 1022 + 6.022 × 1023

= 66.844 × 1022 = 6.68 × 1023 atoms

Answer 2

Answer:

• 6.68 × 10²³

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Hope its helps