3.42 g of sucrose are dissolved in 18 g of water in a beaker. the number of atoms in the solution
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Answer:
66.844×1022=
6.68×1023 atom
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342g sucrose=1 mole
=>3.42g sucrose=0.01 mole=0.01*Na molecules=0.01*Na*45 atoms=0.45*Na atoms
18g water =1mole= Na molecules= 3*Na atoms
Therefore, total atoms=3.45*Na atoms
Na=avogadro’s no.
=>3.42g sucrose=0.01 mole=0.01*Na molecules=0.01*Na*45 atoms=0.45*Na atoms
18g water =1mole= Na molecules= 3*Na atoms
Therefore, total atoms=3.45*Na atoms
Na=avogadro’s no.
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