3.42 g of sucrose are dissolved in 18g of water in a beaker. The number of oxygen atomsin the solution are
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Explanation:
Step 1). Molar mass of sucrose,
<br> or 342g = 1 mole of sucrose. <br> 3.42 g = 0.01 mole of sucrose. <br>
1 mole of sucrose
contains O-atoms =
atoms <br>
0.01 mole of sucrose will contain O-atoms. <br>
atoms =
<br> Step 2: 18 g of water
= 1mole of water. <br> 1 mole of water
contains O-atoms
atoms. <br> step. 3 By adding the number of O-atoms present in 3.42g of sucrose and 18g of water, we get <br>
<br>
atoms.
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