3.42 g of sucrose are dissolved in 18g of water in a beaker. The number of oxygen atoms in the solution are:
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2
Answer:
Explanation:
Molar mass of sucrose = 342 g
No. of oxygen atoms in 342 g of (C
12
H
22
O
11
) =11×N
A
∴ No. of oxygen atoms in 3.42 g of (C
12
H
22
O
11
) =
342
11×N
A
×3.42
= 0.11N
A
No. of oxygen atoms in 18g of H
2
O =1N
A
∴ Total no. of oxygen atoms in 3.42g of sucrose and 18g of water =0.11N
A
+1N
A
=1.11N
A
=1.11×6.02×10
23
=6.68×10
23
.
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3.42 g of sucrose are dissolved in 18g of water in a beaker. The number of oxygen atoms in the solution are:
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