Question

3.42 g of surcose are dissolved in 18 g of water in a beaker. The no. of oxygen atoms in the solution are
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Answer 1

Answer:

6.68 x 10^23

Explanation:

Molar mass of sucrose = 342 g

Sucrose(C12 H22 O11) contains 11 oxygen atoms

⇒11 x 6.022 x 10^23

For 0.01 moles of sucrose

⇒ 0.01 x 11 x 6.022 x 1023

Now, Molar mass of water = H2O = 2 × 1 + 16 = 18g/mol

⇒ Number of moles = 1 Sucrose (H2O) contains 1 oxygen atom = 6.022 × 1023 For 1 mole of water = 6.022 × 1023 Now, add the both values: 6.6 × 1022 + 6.022 × 1023 We get 6.68 × 1023 atoms.

=6.68×10^23