Question

3.42 g sucrose are dissolved in 18 g of water in a beaker. The number of oxygen atoms in the solution are?

with steps​

Answer 1

Answer:

6.68×1023

Explanation:

Molar mass of sucrose = 342 g

No. of oxygen atoms in 342 g of (C12H22O11) =11×NA

∴ No. of oxygen atoms in 3.42 g of (C12H22O11) =34211×NA×3.42 = 0.11NA

No. of oxygen atoms in 18g of H2O =1NA

∴ Total no. of oxygen atoms in 3.42g of sucrose and 18g of water =0.11NA+1NA=1.11NA=1.11×6.02×1023=6.68×1023.