3.42g of sucrose are dissolved in 18g of water in a beaker. The number of oxygen atoms in the solution are
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Explanation:molar mass of sucrose=342
No moles of sucrose=42/342
0.125
1 mole of sucrose has 11 moles of O atom
18g H2O=1 mole H2
1 mole ofH2O has 1 mole of O atom
Total no moles of O atom=1+0.125=1.125 moles
Total no of O atom=6.022×10^23×1.125
=6.789× 10^23
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