Question

3.42g of sucrose is dissolved in 18g of water in a beaker. The number of oxygen atoms in the solution are:-
(a) 6.68 × 10²³
(b) 6.09 × 10²²
(c) 6.022 × 10²³
(d) 6.022 × 10²¹
Also explain it

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Answer 1

Answer:

6.22*10²³

Explanation:

∴ 0.01 mole of sucrose will contain O-atoms. Step 2: 18 g of water (H2O) = 1mole of water. 1 mole of water (H2O) contains O-atoms =6.022×1023 atoms. =66.844×1022=6.68×1023 atoms

Answer 2

Answer:

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