Question

3
46
3 kg
2. The acceleration of the block of mass 3 kg kept on a smooth horizontal surface is
sinus
212N
INF Cos 45
Smooth
(1) 1 m/s2
30N (2) 2 m/s2
(3) 3 m/s2
(4) 4 m/s2
plz solve fst​

Answer 1

The acceleration of the block is 1 m/s²

Therefore, option (1) is correct.

Explanation:

Given:

Force $F_1=2\sqrt{2}$ N acting on block of mass $m=3$ kg

acting at an angle $\theta=45^\circ$

Another force $F_2=1$ N is acting on the block

Resolving the force $F_1$ in horizontal and vertical direction

The horizontal component

$=F_1\cos\theta$

$=2\sqrt{2}\cos 45^\circ$

$=2\sqrt{2}\times\frac{1}{\sqrt{2}}$

$=2$ N

The vertical component

$=F_1\sin\theta$

$=2\sqrt{2}\sin 45^\circ$

$=2\sqrt{2}\times\frac{1}{\sqrt{2}}$

$=2$ N

The vertical force will be balanced by the weight of the body and the nrmal reaction

The net horizontal force will be

$F=2+1=3$ N

From the second law of Newton

We know that

$F=ma$

Where $m$ is mass and $a$ is acceleration

Therefore,

$a=\frac{F}{m}$

$\implies a=\frac{3}{3}=1$ m/s²

Hope this answer is helpful.

Know More:

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Answer 2

REFER THE ABOVE ATTACHMENT

HOPE IT HELPS YOU!