3/4a^2(2/3b^2+8ab) find the product
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Answered by
10
(3/4a)^2 =(9/16a^2)
(2/3B^2)+8AB=(( 4/9B^2)+8AB)
(4/9b^2+8ab)= 4+a^2 b^3/ab^2
(9/16a^2) (4/9b^2)+8ab) = (9/16a^2)* (4/ab^2)+(a^2 b^3/ab^2)
9/a^3 b^2+a^2 b^3/ab^2 =a+a^4 b^3/a^3 b^2
Answered by
11
Answer:
a+a^4b^3/a^3b^2
Step-by-step explanation:
3/4a)^2 =(9/16a^2)
(2/3B^2)+8AB=(( 4/9B^2)+8AB)
(4/9b^2+8ab)= 4+a^2 b^3/ab^2
(9/16a^2) (4/9b^2)+8ab) = (9/16a^2)* (4/ab^2)+(a^2 b^3/ab^2)
9/a^3 b^2+a^2 b^3/ab^2 =a+a^4 b^3/a^3 b^2
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