Math, asked by varghesevattalil1942, 9 months ago

(3/4a-4/3b) whole square 2

Answers

Answered by mankaovi1025
1

Answer:

Step-by-step explanation:

(3/4a-4/3/b)^2                                  (a-b)^2 = a^2+b^2-2ab

(3/4a)^2 + (4/3b)^2 -2/4/3*3/4

9/16a^2 + 16/9b^2 - 2

Hope it help. Please mark it as the brainliest...

Answered by Sugandhithakur
0

Answer:

( \frac{3}{4} a -  \frac{4}{3} b)^{2} \\ (a - b) {}^{2}  =  {a}^{2}  +  {b}^{2}  - 2ab \\  =\frac{9}{16} a {}^{2}  +  \frac{16}{9} b {}^{2}  - 2ab

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