Question

(3/4a2+3b2)4(a2-2/3b2)

Answer 1

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$= (\frac{3}{4a2} + 3b2 )4( \frac{a2 - 2}{3b2} )$

$=( \frac{3}{8a} + 6b) \: \times 2 \times \frac{2a - 2}{3b}$

$= \frac{3 + 48ab}{8a} \times 2 \times \frac{2a - 2}{3b}$

$= \frac{3 + 48ab}{8a} \times 2 \times \frac{2a - 1}{3b}$

$= \frac{3 + 48ab}{4a} \times \frac{2(a - 1)}{3b}$

$= \frac{3(1 + 16ab)}{2a} \times \frac{a - 1}{3b}$

$= \frac{(1 + 16ab) \times (a - 1)}{2ab}$

$= \frac{a - 1 + 16a {}^{2} b - 16ab}{2ab}$

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Answer 2

Step-by-step explanation:

(

4a2

3

+3b2)4(

3b2

a2−2

)

=( \frac{3}{8a} + 6b) \: \times 2 \times \frac{2a - 2}{3b}=(

8a

3

+6b)×2×

3b

2a−2

= \frac{3 + 48ab}{8a} \times 2 \times \frac{2a - 2}{3b}=

8a

3+48ab

×2×

3b

2a−2

= \frac{3 + 48ab}{8a} \times 2 \times \frac{2a - 1}{3b}=

8a

3+48ab

×2×

3b

2a−1

= \frac{3 + 48ab}{4a} \times \frac{2(a - 1)}{3b}=

4a

3+48ab

×

3b

2(a−1)

= \frac{3(1 + 16ab)}{2a} \times \frac{a - 1}{3b}=

2a

3(1+16ab)

×

3b

a−1

= \frac{(1 + 16ab) \times (a - 1)}{2ab}=

2ab

(1+16ab)×(a−1)

= \frac{a - 1 + 16a {}^{2} b - 16ab}{2ab}=

2ab

a−1+16a

2

b−16ab