3. За – 4b + 4с, 2а + 3b – 8с, а — 6b+c
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Answer:
After adding we get:
(3a−4b+4c)+(2a+3b−8c)+(a−6b+c)
=3a+2a+a−4b+3b−6b+4c−8c+c
=6a−7b−3c
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