Chemistry, asked by 10zom, 19 days ago

3.4g of a gas at STP occupies 2.24l. what is its malecular mass.​

Answers

Answered by sasmithayamini12
1

Answer:

CHEMISTRY

4.4 g of a gas at STP occupies a volume of 2.24 L. The gas can be:

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ANSWER

4.4 g of a gas at STP occupies a volume of 2.24 L. The gas can be CO

2

At STP, 1 mole of any gas occupies a volume of 22.4 L.

4.4 g of a gas at STP occupies a volume of 2.24 L.

Hence, the number of moles of gas =

22.4

2.24

=0.1 moles.

0.1 moles of a gas = 4.4 g.

1 mole of a gas =4.4×

0.1

1

=44 g.

Thus, the molecular weight of gas is 44 g/mol. It is the molecular weight of CO

2

gas.

Answered by GSSanskruti
1

4.4 g of a gas at STP occupies a volume of

2.24 L. The gas can be CO2

At STP, 1 mole of any gas occupies a volume of 22.4 L.

4.4 g of a gas at STP occupies a volume of

2.24 L.

Hence, the number of moles of gas =

2.24/22.4 =0.1 moles.

0.1 moles of a gas = 4.4 g.

1 mole of a gas =4.4× 1/0.1

=44 g.

Thus, the molecular weight of gas is 44 g/mol. It is the molecular weight of CCO gas.

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