3.4g of a gas at STP occupies 2.24l. what is its malecular mass.
Answers
Answer:
CHEMISTRY
4.4 g of a gas at STP occupies a volume of 2.24 L. The gas can be:
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ANSWER
4.4 g of a gas at STP occupies a volume of 2.24 L. The gas can be CO
2
At STP, 1 mole of any gas occupies a volume of 22.4 L.
4.4 g of a gas at STP occupies a volume of 2.24 L.
Hence, the number of moles of gas =
22.4
2.24
=0.1 moles.
0.1 moles of a gas = 4.4 g.
1 mole of a gas =4.4×
0.1
1
=44 g.
Thus, the molecular weight of gas is 44 g/mol. It is the molecular weight of CO
2
gas.
4.4 g of a gas at STP occupies a volume of
2.24 L. The gas can be CO2
At STP, 1 mole of any gas occupies a volume of 22.4 L.
4.4 g of a gas at STP occupies a volume of
2.24 L.
Hence, the number of moles of gas =
2.24/22.4 =0.1 moles.
0.1 moles of a gas = 4.4 g.
1 mole of a gas =4.4× 1/0.1
=44 g.
Thus, the molecular weight of gas is 44 g/mol. It is the molecular weight of CCO gas.