Question

(3)
4ML?
5ML
3
2.
If the moment of inertia of a solid sphere of mass
Mand radius R about an axis passing through its
centre of mass is MR2, then its radius of gyration about an axis which is parallel to given axis and at a distance 2R from the centre will be​

Answer 1

Answer:

$\sqrt{5} r$

Explanation:

According to parallel axes theorem,

$i = m {r}^{2} + m {(2r)}^{2} = m {r}^{2} + 4m {r}^{2} = 5m {r}^{2}$

$m {k}^{2} = 5m {r}^{2} \\ where \: k \: is \: radius \: of \: gyration$

${k }^{2} = 5 {r }^{2} \\ k = \sqrt{5} r$