Question

(і) а = 3 + 4n write sequence with nth term in arithmatic progression form​

Answer 1

Answer:

in given problem I am given the sequence with the nth term (an)

an= 3+ 4n

so subsutituting n = 1 we get

a1 = 3 + 4(1)

a1 = 7

substituting n = 2 we get

a2 = 3 + 4 (2)

a2 = 11

substituting n = 3 we get

a3 = 3 + 4(3)

a3 = 15

common difference (d) = a2 - a1 = a3 - a2

here ' a_2 - a_1 = 11 - 7

= 4

also

a3 - a2 = 15 - 11

= 4

since a2 - a1 = a3 - a2

hence the given sequence is an A.P

Answer 2

Answer:

7,11,15,19

Step-by-step explanation:

a=3+4n

when n (1)

• then a=3+4(1)

=11

when n(2)

• then a=3+4(2)

=15

And so on