Question

3-4sin^2a/cos^a=3-tan^2a

Answer 1

can i know what to prove please
got it but I don't think it is right but it may help you to solve it
LHS
(3-4sin^2a)/cos^a
=(3-3sin^2a-sin^2a)/cos^a
=(3{1-sin^2a}-sin^2a)/cos^a
=(3cos^2a-sin^2a)/cos^a
=(3cos^2a/cos^a)- (sin^2a/cos^a)
now divide whole eq with cos^a
=3-tan^2a