Question

3(4x+1)-(4x-1)=2(x+5)​

Answer 1

→ 3(4x + 1) - (4x - 1) = 2(x + 5)

→ 12x + 3 - 4x + 1 = 2(x + 5)

→ (12 - 4)x + (3 + 1) = 2(x + 5)

→ 8x + 4 = 2(x + 5)

→ 4(2x + 1) = 2(x + 5)

$= > \dfrac{4(2x + 1)}{2} = x + 5 \\ \\ = > 2(2x + 1) = x + 5$

→ 4x + 2 = x + 5

→ 4x - x = 5 - 2

→ 3x = 3

$= > \dfrac{3x}{3} = \dfrac{3}{3}$

→ x = 1

Answer 2

$\huge\mathcal\orange{Your}$$\huge\mathcal\red{Answer→}$

$\huge\red{→}$ 3(4x+1)-(4x-1) = 2(x+5)

$\huge\red{→}$ 12x + 3 - 4x + 1 = 2x + 10

$\huge\red{→}$ 8x + 4 = 2x + 10

$\huge\red{→}$ 8x + 4 - 2x = 10

$\huge\red{→}$ 6x = 10 - 4

$\huge\red{→}$ 6x = 6

$\huge\red{→}$ x = $\huge\frac{6}{6}$

$\huge\red{→}$ x = 1