Question

3/4x - 2/3y =1 || 3/8x - 1/6y = 1 find the sameltaneous linear equations​

Answer 1

Answer:

x=4,y=3

Step-by-step explanation:

$\frac{3}{4} x - \frac{2}{3} y - 1 = 0\\ \frac{3}{8} x - \frac{1}{6} y - 1 = 0$

By cross multiplication,

$x = (( - \frac{2}{3} \times - 1) - ( - \frac{1}{6} \times - 1)) \div (( \frac{3}{4} \times - \frac{1}{6} ) - (\frac{3}{8} \times - \frac{2}{3} )$

$x = \frac{ \frac{2}{3} - \frac{1}{6} }{ - \frac{3}{24} + \frac{6}{24} } = 4$

by substituting x=4

$y = (1 - \frac{3}{4} x) \div \frac{ - 2}{3}$

$y = 3$