Question

3/4x^2 -x - 1=0


Find using quadratic formula. class10. ​

Answer 1

Answer:

hi friend I think ur question is 3x²/4 - x - 1 = 0 in that case answer is below

Step-by-step explanation:

3x²/4 - x - 1 = 0

( 3x²-4x-4 )/4 = 0 { Taking LCM }

3x² - 4x - 4 = 0. { multiply 4 both sides}

ax² + bx + c = 0

a = 3 , b = -4 , c = -4

x = ( -b ± √[b²-4ac] )/2a

x = ( -(-4) ± √[(-4)²-4(3)(-4) )/2(3)

x = [ 4 ± √64 ]/6

x = (4 ± 8 )/6

case(I)

x = ( 4 + 8 )/6 = 12/6 = 2

case(II)

x = ( 4 - 8 )/6 = -1/3

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Answer 2

ANSWER:

To Solve:

• 3/4x² - x - 1 = 0

Solution:

$\text{We are given that,}\\\\:\longrightarrow\dfrac{3}{4}x^2-x-1=0\\\\\text{Multiplying the equation by 4,}\\\\:\implies3x^2-4x-4=0\\\\\text{We know that,}\\\\\text{For a quadratic equation, ax^2+bx+c=0 ,}\\\\\text{By Quadratic Formula,}\\\\:\hookrightarrow x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\\text{So, in this case, a = 3, b = -4, c = -4.}\\\\\text{Hence,}\\\\:\implies x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\:\implies x=\dfrac{-(-4)\pm\sqrt{(-4)^2-4(3)(-4)}}{2(3)}$

$:\implies x=\dfrac{+4\pm\sqrt{16+48}}{6}\\\\:\implies x=\dfrac{4\pm\sqrt{64}}{6}\\\\:\implies x=\dfrac{4\pm8}{6}\\\\:\implies x=\dfrac{2\!\!\!/\:(2\pm4)}{6\!\!\!/_{\:3}}\\\\:\implies x=\dfrac{2+4}{3}\:\:or\:\:x=\dfrac{2-4}{3}\\\\:\implies x=\dfrac{6\!\!\!/^{\:2}}{3\!\!\!/}\:\:or\:\:x=\dfrac{-2}{3}\\\\:\implies x=2\:\:and\:\:x=\dfrac{-2}{3}\\\\\text{So,}\\\\\bf{:\implies x=2\:\:and\:\:\dfrac{-2}{3}}$

Formula Used:

$\text{For a quadratic equation, ax^2+bx+c=0 ,}\\\\\text{By Quadratic Formula,}\\\\:\hookrightarrow x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$