Question

3/4x^2-x-1=0 solve it by quadratic formula

Answer 1

Answer:

PLEASE MARK AS BRAINLIEST

Step-by-step explanation:

$3/4x^2-x-1=0\\\\we know ,\\x=-\sqrt[ b +-]{b^2-4ac/2a\\}\\b^2-4ac=(-1)^2-4(\frac{3}{4})(-1)\\ =4\\-> x=+1\sqrt[+-]{\frac{4}{2(\frac{3}{4})} } \\..>\frac{10}{3} or 2$