Question

-3/4x^2yz^3 by -2/3x^2yz
divide the problem​

Answer 1

Answer:

Step-by-step explanation:

Given: 2x=3y=12z  

Required to prove:

x=2yzy−z  

Simplifying,

1x=y−z2yz  

1x=y2yz−z2yz  

1x=12z−12y  

1x=1/2⋅(1z−1y)  

We can divide by x,y and z because they are not zero. While this does satisfy the given but the value of the statement we are required to prove becomes undefined.

Now, let

2x=3y=12z=k  

Then,

2x=k→2=k1x  

3y=k→3=k1y  

12z=k→12=k1z  

So,

12=k1z  

12/3=k1zk1y  

4=k1zk1y  

4=k1z−1y  

41/2=(k1z−1y)12  

2=(k12z−12y)  

k1x=(k12z−12y)  

Comparing exponents,

1x=(12z−12y)  

[Remember this?]

1x=y−z2yz  

x=2yzy−z