3-4x<x-12,x€{-1,0,1,2,3,4,5,6,7}
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Answer:
3−4x<x−12
Subtracting 3 from both sides
⟹−3+3−4x<x−12−3
⟹−4x<x−15
Subtracting x from both sides
⟹−4x−x<x−x−15
⟹−5x<−15 ⟹x>3
(Dividing by -5 and reverse the symbols)
As xϵ−1,0,1,2,3,4,5,6,7
The solution set= { 4, 5, 6, 7}
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