Question

3( 4y – 1 ) – 2( 1 – y ) = 23

Answer 1

$\huge \fbox \purple{❥ Answer}$

$3(4y - 1) - 2(1 - y) = 23$

$12y - 3 - 2 + 2y = 23$

$12y + 2y - 3 - 2 = 23$

$14y - 5 = 23$

$14y = 23 + 5$

$14y = 28$

$y = 28 \div 14$

$y = 2$

So,y = 2

Answer 2

(4y−1)−2(1−y)=23

12y - 3 - 2 + 2y = 2312y−3−2+2y=23

12y + 2y - 3 - 2 = 2312y+2y−3−2=23

14y - 5 = 2314y−5=23

14y = 23 + 514y=23+5

14y = 2814y=28

y = 28 \div 14y=28÷14

y = 2y=2

So,y = 2

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