3=4y+3 ,7y=5x+1 solve by substitution x>y
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Given :
- 4y + 3 = 3
- 7y = 5x + 1
To Find :
- The value of x and y
Solution :
Given :
4y + 3 = 3
7y = 5x + 1
To Find :
The value of x and y
Solution :
4y + 3 = 3 ————(1)
7y = 5x + 1 ————(2)
From eq (1)
→ 4y + 3 = 3
→ 4y = 3 - 3
→ y = 0/4
→ y = 0
Putting ( y = 0 ) in eq (2)
→ 7y = 5x + 1
→ 7(0) = 5x + 1
→ 0 = 5x + 1
→ 5x + 1 = 0
→ 5x = - 1
→ x = - 1/5
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