Question

√3+√5+1/√3+√5 rationalized this equation

Answer 1

√3+√5+1/√3+√5

Rationalising factor = √3-√5

→ (√3+√5+1)(√3-√5)/(√3+√5)(√3-√5)

→ √3(√3-√5)+√5(√3-√5)+1(√3-√5)/(√3²-√5²)

→ (3-√15+√15-5+√3-√5)/(3-5)

→ (-2+√3-√5)/-2

-(-2+√3-√5)/2

(2-√3+√5)/2

hope it helps

Answer 2

Hello dear !
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$\frac{ \sqrt{3} + \sqrt{5} +1}{ \sqrt{3} + \sqrt{5} }$

Rationalising the denominator 

$\frac{ (\sqrt{3} + \sqrt{5}+1) ( \sqrt{3} - \sqrt{5} )}{( \sqrt{3})^2 - (\sqrt{5}) ^2 }$

$\frac{3- \sqrt{15} + \sqrt{15}- 5 + \sqrt{3} - \sqrt{5} }{3-5}$

$\frac{3+\sqrt{3}-5- \sqrt{5} }{-2}$

$\frac{2- \sqrt{3}+ \sqrt{5} }{2}$