3+√5÷2√5+3=a+b√5 find value of rational number a and b
Answers
Answered by
2
3+√5/2√5+3=a+b√5 Rationalising LHS, 3+√5/2√5+3*2√5-3/2√5-3 =3(2√5-3)+√5(2√5-3)/(2√5)^2-(3)^2 =6√5-9+10-3√5/20-9 =3√5+1/11 LHS=RHS 3√5+1/11=a+b√5 a=1/11, b=3/11
Similar questions