Question

3-5√2 is an irrational number​

Answer 1

Answer:

To prove = 3-5√2 is irrational no.

Solution :-

Assume that 3-5√2 is rational no. then it can be written in p/q form where q is not equal to 0.

3-5√2 = p/q

5√2 = p/q -3

5√2 = p - 3q/q

√2 = p-3q/ 5q

This give that √2 is a rational no. but the fact is √2 is irrational therefore this contract our assumption and prove that 3-5√2 is irrational no.

~ Nikhra❤️