Question

3^-5 × 3^2 ÷ 3^-6 +(2^2×3)^2 +(2/3)^-1 + 2^-1 +(1/19)^-1 in expotential form​

Answer 1

Answer:

3

−5

×3

2

÷3

−6

+(2

2

×3)

2

+(2/3)

−1

+2

−1

+(1/19)

−1

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Answer

Let us simplify,

3

−5

×3

2

÷3

−6

+(2

2

×3)

2

+(2/3)

−1

+2

−1

+(1/19)

−1

=3

−5+2+6

+(2

4

×3

2

)+3/2+1/2+19

1

=3

3

+(16×9)+4/2+19

=27+144+2+19

=192

The exponential form is 192.