3-√5/3+2√5= a√5- (19/11)
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Answers
Answered by
2
Answer:
=(3-√5)/(3+2√5)
=(3-√5)/(3+2√5)×(3-2√5)/(3-2√5)
=(3-√5)(3-2√5)/(3+2√5)(3-2√5)
=[3(3-2√5)-√5(3-2√5)]/(3²-(2√5)²
=(3²-6√5-3√5+2(5))/(9-4(5)
=(9-9√5+10)/(9-20)
=(19-9√5)/(-11)
=–(19-9√5)/ 11
= –(19-9√5)/11
=(-19+9√5)/11
=(9√5-19)/11
=9√5/11 - 19/11 = a√5-19/11
Therefore,a=9/11
If it is (a√5-19)/11 then a=9
But according to question,a√5-19/11
So,answer is 9/11
Answered by
1
Step-by-step explanation:
Step-by-step explanation:
=(3-√5)/(3+2√5)
=(3-√5)/(3+2√5)×(3-2√5)/(3-2√5)
=(3-√5)(3-2√5)/(3+2√5)(3-2√5)
=[3(3-2√5)-√5(3-2√5)]/(3²-(2√5)²
=(3²-6√5-3√5+2(5))/(9-4(5))
=(9-9√5+10)/(9-20)
=(19-9√5)/(-11)
=–(19-9√5)/ 11
= –(19-9√5)/11
=(-19+9√5)/11
=(9√5-19)/11
=9√5/11 - 19/11 = a√5-19/11
Therefore,a=9/11
If it is (a√5-19)/11 then a=9
But according to question,a√5-19/11
So,answer is 9/11
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