Math, asked by vermapriyanka3558, 11 months ago

3-√5/3+2√5 rationalise

Answers

Answered by Anonymous
3

ANSWER :

\dfrac{3-√5}{3+2√5}

\dfrac{3-√5}{3+2√5}×\dfrac{3-25}{3-2√5}

\dfrac{9 + 10}{9 - 5}

\dfrac{19}{4}

Answered by Aparna2904
1

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