Question

(3+√5) (3-√5) /√3+ √2i)-((-√3+√2i)) a+ib​

Answer 1

Given expression

Given expression(

Given expression( 3

Given expression( 3

Given expression( 3 +

Given expression( 3 + 2

Given expression( 3 + 2

Given expression( 3 + 2 )i−(

Given expression( 3 + 2 )i−( 3

Given expression( 3 + 2 )i−( 3

Given expression( 3 + 2 )i−( 3 −

Given expression( 3 + 2 )i−( 3 − 2

Given expression( 3 + 2 )i−( 3 − 2

Given expression( 3 + 2 )i−( 3 − 2 i)

Given expression( 3 + 2 )i−( 3 − 2 i)(3+i

Given expression( 3 + 2 )i−( 3 − 2 i)(3+i 5

Given expression( 3 + 2 )i−( 3 − 2 i)(3+i 5

Given expression( 3 + 2 )i−( 3 − 2 i)(3+i 5 )(3−i

Given expression( 3 + 2 )i−( 3 − 2 i)(3+i 5 )(3−i 5

Given expression( 3 + 2 )i−( 3 − 2 i)(3+i 5 )(3−i 5

Given expression( 3 + 2 )i−( 3 − 2 i)(3+i 5 )(3−i 5 )

Given expression( 3 + 2 )i−( 3 − 2 i)(3+i 5 )(3−i 5 )

Given expression( 3 + 2 )i−( 3 − 2 i)(3+i 5 )(3−i 5 )

Given expression( 3 + 2 )i−( 3 − 2 i)(3+i 5 )(3−i 5 ) =

Given expression( 3 + 2 )i−( 3 − 2 i)(3+i 5 )(3−i 5 ) = 2

Given expression( 3 + 2 )i−( 3 − 2 i)(3+i 5 )(3−i 5 ) = 2 2

Given expression( 3 + 2 )i−( 3 − 2 i)(3+i 5 )(3−i 5 ) = 2 2

Given expression( 3 + 2 )i−( 3 − 2 i)(3+i 5 )(3−i 5 ) = 2 2 i

Given expression( 3 + 2 )i−( 3 − 2 i)(3+i 5 )(3−i 5 ) = 2 2 i(9−5i

Given expression( 3 + 2 )i−( 3 − 2 i)(3+i 5 )(3−i 5 ) = 2 2 i(9−5i 2

Given expression( 3 + 2 )i−( 3 − 2 i)(3+i 5 )(3−i 5 ) = 2 2 i(9−5i 2 )

Given expression( 3 + 2 )i−( 3 − 2 i)(3+i 5 )(3−i 5 ) = 2 2 i(9−5i 2 )

Given expression( 3 + 2 )i−( 3 − 2 i)(3+i 5 )(3−i 5 ) = 2 2 i(9−5i 2 )

Given expression( 3 + 2 )i−( 3 − 2 i)(3+i 5 )(3−i 5 ) = 2 2 i(9−5i 2 ) =

Given expression( 3 + 2 )i−( 3 − 2 i)(3+i 5 )(3−i 5 ) = 2 2 i(9−5i 2 ) = 2

Given expression( 3 + 2 )i−( 3 − 2 i)(3+i 5 )(3−i 5 ) = 2 2 i(9−5i 2 ) = 2 2

Given expression( 3 + 2 )i−( 3 − 2 i)(3+i 5 )(3−i 5 ) = 2 2 i(9−5i 2 ) = 2 2

Given expression( 3 + 2 )i−( 3 − 2 i)(3+i 5 )(3−i 5 ) = 2 2 i(9−5i 2 ) = 2 2 i

Given expression( 3 + 2 )i−( 3 − 2 i)(3+i 5 )(3−i 5 ) = 2 2 i(9−5i 2 ) = 2 2 i14

Given expression( 3 + 2 )i−( 3 − 2 i)(3+i 5 )(3−i 5 ) = 2 2 i(9−5i 2 ) = 2 2 i14

Given expression( 3 + 2 )i−( 3 − 2 i)(3+i 5 )(3−i 5 ) = 2 2 i(9−5i 2 ) = 2 2 i14 ×

Given expression( 3 + 2 )i−( 3 − 2 i)(3+i 5 )(3−i 5 ) = 2 2 i(9−5i 2 ) = 2 2 i14 × i

Given expression( 3 + 2 )i−( 3 − 2 i)(3+i 5 )(3−i 5 ) = 2 2 i(9−5i 2 ) = 2 2 i14 × ii

Given expression( 3 + 2 )i−( 3 − 2 i)(3+i 5 )(3−i 5 ) = 2 2 i(9−5i 2 ) = 2 2 i14 × ii

Given expression( 3 + 2 )i−( 3 − 2 i)(3+i 5 )(3−i 5 ) = 2 2 i(9−5i 2 ) = 2 2 i14 × ii

Given expression( 3 + 2 )i−( 3 − 2 i)(3+i 5 )(3−i 5 ) = 2 2 i(9−5i 2 ) = 2 2 i14 × ii =

Given expression( 3 + 2 )i−( 3 − 2 i)(3+i 5 )(3−i 5 ) = 2 2 i(9−5i 2 ) = 2 2 i14 × ii = 2

Given expression( 3 + 2 )i−( 3 − 2 i)(3+i 5 )(3−i 5 ) = 2 2 i(9−5i 2 ) = 2 2 i14 × ii = 2

Given expression( 3 + 2 )i−( 3 − 2 i)(3+i 5 )(3−i 5 ) = 2 2 i(9−5i 2 ) = 2 2 i14 × ii = 2

Given expression( 3 + 2 )i−( 3 − 2 i)(3+i 5 )(3−i 5 ) = 2 2 i(9−5i 2 ) = 2 2 i14 × ii = 2 −7i

Given expression( 3 + 2 )i−( 3 − 2 i)(3+i 5 )(3−i 5 ) = 2 2 i(9−5i 2 ) = 2 2 i14 × ii = 2 −7i

Given expression( 3 + 2 )i−( 3 − 2 i)(3+i 5 )(3−i 5 ) = 2 2 i(9−5i 2 ) = 2 2 i14 × ii = 2 −7i ⇒a=0,b=

Given expression( 3 + 2 )i−( 3 − 2 i)(3+i 5 )(3−i 5 ) = 2 2 i(9−5i 2 ) = 2 2 i14 × ii = 2 −7i ⇒a=0,b= 2

Given expression( 3 + 2 )i−( 3 − 2 i)(3+i 5 )(3−i 5 ) = 2 2 i(9−5i 2 ) = 2 2 i14 × ii = 2 −7i ⇒a=0,b= 2

Given expression( 3 + 2 )i−( 3 − 2 i)(3+i 5 )(3−i 5 ) = 2 2 i(9−5i 2 ) = 2 2 i14 × ii = 2 −7i ⇒a=0,b= 2

Given expression( 3 + 2 )i−( 3 − 2 i)(3+i 5 )(3−i 5 ) = 2 2 i(9−5i 2 ) = 2 2 i14 × ii = 2 −7i ⇒a=0,b= 2 −7

Given expression( 3 + 2 )i−( 3 − 2 i)(3+i 5 )(3−i 5 ) = 2 2 i(9−5i 2 ) = 2 2 i14 × ii = 2 −7i ⇒a=0,b= 2 −7

Answer 2

Answer:

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