Question

3-√5/4-2√5 rationalize the denominator​

Answer 1

Answer:

$\frac{3 - \sqrt{5} }{4 - 2 \sqrt{5} } \\ = \frac{3 - \sqrt{5} }{4 - 2 \sqrt{5} } \times \frac{4 + 2 \sqrt{5} }{4 + 2 \sqrt{5} } \\ = \frac{12 + 6 \sqrt{5} - 4 \sqrt{5} - 2 \sqrt{25} }{16 - 4 \sqrt{25} } \\ = \frac{12 + (6 - 4 )\sqrt{5} - (2 \times 5) }{16 - (4 \times 5)} \\ = \frac{12 + 2 \sqrt{5} - 10 }{16 - 20} \\ = \frac{12 + 2 \sqrt{5} - 10 }{ - 4}$