3 +√5 +√6 / 2√5 rationalize the denominato
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Rationalize the denominator and simplify √5/√6+2-√5/√6-2 ... The sum of all odd integers between 2 to 100 divisible by 3 Write ...
Step-by-step explanation:√5/√6+2-√5/√6-2=[√5*(√6-2 )/(√6+2)*(√6-2)]-[√5*(√6+2)/(√6-2)*(√6+2)]=(√30-2√5)/(6-2√6+2√6-4)-(√30+2 ...
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