3×5+6×P+Q×5 =64 ,Q is 1 more than P.Then ,p,+Q=?
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2
Answer:
Given A and B are two sets with number of elements p and q respectively.
The cartesian product of A and B=A×B={(a,b):(a∈A) and (b∈B)}
Number of elements in A×B=∣A×B∣=∣A∣.∣B∣=pq
Any relation from A to B is a subset of A×B.
Hence number of relations from A to B is the number of subsets of A×B
=2
∣A×B∣
=2
pq
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1
Answer:
9 is the correct answer
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