Question

3×5+6×P+Q×5 =64 ,Q is 1 more than P.Then ,p,+Q=?​

Answer 1

Step-by-step explanation:

Given:

$q = p + 1$

According to the question,

$3 \times 5 + 6 \times p + q \times 5 = 64$

$15 + 6p + 5q = 64$

$6p + 5q = 64 - 15$

$6p + 5q = 49$

Putting value of 'Q' in above equation,

$6p + 5(p + 1) = 49$

$6p + 5p + 5 = 49$

$6p + 5p = 49 - 5$

$11p = 44$

$p = 4$

Therefore, from value of 'p', we get,

$q = p + 1 = 4 + 1 = 5$

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Answer 2

Step-by-step explanation:

3×5+6×P+Q×5=64

15+6×P+(1+P)×5=64

21×P+5+5P=64

21P+5+5P=64

26P+5=64

26P=64-5

26P=59

P=59/26

P+Q=

59/26+59/26+1

59/26+59+26/26 (taking LCM)

59/26+85/26

144/26

=4

Hence Done

Hope it helps