Question

[3^5]^7=(3) ^p^-3 determine p in the following​

Answer 1

${( {3}^{5}) }^{7} = {( {3}^{p} )}^{ - 3}$

$({3})^{5 \times 7} = ({3})^{ - 3p}$

Comparing both powers

5×7=-3p

p=

$- \frac{35}{3}$