Question

3(5/8)-(3/8-(3/4+5/8) solve by bodmas rule.

Answer 1

Answer:

$3{ \huge(} \dfrac{5}{8} { \huge)} - { \huge(} \dfrac{3}{8} { \huge) } - { \huge(} \dfrac{3}{4} + \dfrac{5}{8} { \huge)}$

B - Bracket

O - Off

D - Division

M - Multiplication

A- Addition

S - Substraction

Now, BODMAS states that first we will remove bracket.

$= 3{ \huge(} \dfrac{5}{8} { \huge)} - { \huge(} \dfrac{3}{8} { \huge) } - { \huge(} \dfrac{6 + 5}{8} { \huge)}$

$= 3{ \huge(} \dfrac{5}{8} { \huge)} - { \huge(} \dfrac{3}{8} { \huge) } - { \huge(} \dfrac{11}{8} { \huge)}$

$= 3 \times \dfrac{5}{8} - { \huge(} \dfrac{3}{8} { \huge) } - { \huge(} \dfrac{11}{8} { \huge)}$

$= \dfrac{15}{8} - { \huge(} \dfrac{3}{8} { \huge) } - { \huge(} \dfrac{11}{8} { \huge)}$

$= \dfrac{15}{8} - \dfrac{3}{8} - \dfrac{11}{8}$

$= \dfrac{15 - 3 - 11}{8}$

$= \dfrac{15 - 14}{8}$

$= \dfrac{1}{8}$

$= \dfrac{1}{8}$ Ans.

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