3√5-8 is irrational number
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Let 3√5-8 be a rational number.
A rational number is in the form of p/q where p,q are integers.
3√5-8 = p/q
3√5 = p/q + 8
3√5 = (p+8q)/q
√5 = (p+8q)/3q
p,q are integers then (p+8q)/3q is a rational number.
Then, √5 also must be a rational number,
But this contradicts the fact that √5 is an irrational number.
So,our supposition is false.
Therefore, 3√5-8 is an irrational number.
Hence proved.
A rational number is in the form of p/q where p,q are integers.
3√5-8 = p/q
3√5 = p/q + 8
3√5 = (p+8q)/q
√5 = (p+8q)/3q
p,q are integers then (p+8q)/3q is a rational number.
Then, √5 also must be a rational number,
But this contradicts the fact that √5 is an irrational number.
So,our supposition is false.
Therefore, 3√5-8 is an irrational number.
Hence proved.
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0
Answer:
3 is not rational number and 3 is not irrational number
Step-by-step explanation:
it is a lucky number
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