Math, asked by tejrai987, 9 months ago

√3^5*a^2= 3^a*3√3
Find the value of a​

Answers

Answered by raushan6198
1

Answer:

 \sqrt{ {3}^{5} }  \times  {a}^{2}  =  {3}^{a}  \times 3 \sqrt{3}  \\  \sqrt{9 \times 9 \times 3}  \ \times  {a}^{2}  =  {3}^{a}  \times 3 \sqrt{3} \\ 9 \sqrt{3}  \times  {a}^{2}   =  {3}^{a}  \times 3 \sqrt{3}  \\ 3 {a}^{2}  =  {3}^{a}  \\  {a}^{2} =  {3}^{a - 1}

a= 1(by hit and trial)

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