Question

3.5 centimetre high object is placed at a distance of 12 cm from a concave lens of focal length 16cm find the size of the image

Answer 1

Given

U = -12 cm

f = -16 cm

ho= 3.5cm

Now

$= > \frac{1}{f} = \frac{1}{v} - \frac{1}{u} \\ = > \frac{1}{ -16} = \frac{1}{v} + \frac{1}{12} \\ = > \frac{1}{v} = \frac{ - 1}{16} - \frac{1}{12} \\ = > v = \frac{-48}{7}\\ Now \: \\ = > m = \frac{ v}{u} = \frac{he}{ho} \: \: \\ = > \frac{ - 48}{ 7}×\frac{-1}{12} = \frac{he}{3.5} \: = > he = 2 cm \\ \\ hence \: Height \: of \: body \: is \: 2 \:cm$

Answer 2

Answer:

2 cm !!!!!!!!!!!!!

Explanation:

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