Question

3.5 gm of solid Barium fluoride is added to water forming 1 lit  of solution at . Solubility product of

the salt is . What will be the minimum volume of water (in litres)  to be added to above solution to

dissolve the salt completely.

( At. Wt. of Ba =137, F= 19)​

Answer 1

Answer:

Explanation:

hope it helps this pdf

31e1f984396d5915e1de475bc324605b.pdf

Answer 2

Given:

3.5gm of solid Barium fluoride is added to water formng 1l solution at 25 deg C. Solubility product of salt is 4.6*10-6. ( atomic wt of Ba = 137 and F-19)

To find:

What wil be the minimum volume of water to be added to above solution to dissolve the salt completely.

Solution:

From given, we have,

3.5gm of solid Barium fluoride is added to water forming 1l solution at 25 deg C. Solubility product of salt is 4.6*10-6. ( atomic wt of Ba = 137 and F-19)

For the complete dissolution of the  salt,  

Ksp  =  [Ba2+] [F-1]2

Let S mol / L be the solubility of the salt, then  

Ksp  = S3 = 4.6 × 10-6 ,  

or  S = 1.66 × 10-2 M

Let V litre of the water is added for making the saturated solution,  

Now the molar mass of the substance  

=  137 + 2 × 19 = 175 gm / mol  

Initial no. of moles =  3.5 / 175  =  0.02  

Using the molarity equation,  

Initial no. of moles of the salt = no. of moles of the salt in solution  

0.02  =  1.66 × 10-2 × V  

V =    1.2 L

The minimum litres of water is 1.2 l.